[SIPForum-discussion] Question about SUBSCRIBE method processing in proxy

[Yevgen Krapiva]

I mean "Not implemented".

For example, XLite endlessly sends SUBSCRIBE request until I respond
with Method Not Allowed, and only then it shuts up.

2009/4/17, Tomasz Zieleniewski <tzieleniewski at gmail.com>:
> what do You mean by "doesn't support them?
>
> 2009/4/17 Yevgen Krapiva <ykrapiva at gmail.com>:
>> Thanks.
>>
>> But I'm thinking about if proxy recognizes *special* requests but
>> doesn't support them then should it response Method Not Allowed or
>> just ignore and apply standart routing methods for them ?
>>
>> I want to apply polite solution in my proxy.
>>
>> 2009/4/17, Tomasz Zieleniewski <tzieleniewski at gmail.com>:
>>> Hi,
>>>
>>> If the requestURI sip:user1 at kv-po-ykrapivanb.umc.com.ua
>>> is a correct AOR for this user and proxy doesn't provide service for
>>> this
>>> particular event package then it is completely normal behavior to send
>>> the request further to the destination.
>>> If proxy handles user domain then by making a query to location service
>>> and if not then by applying standard routing procedures.
>>>
>>> Kind regards,
>>> - Tomasz Zieleniewski
>>>
>>> 2009/4/16 Yevgen Krapiva <ykrapiva at gmail.com>:
>>>> Hi.
>>>>
>>>> Here is short description of incoming SUBSCRIBE request:
>>>>
>>>>>SUBSCRIBE sip:user1 at kv-po-ykrapivanb.umc.com.ua SIP/2.0
>>>>>Via: SIP/2.0/UDP
>>>>> 172.20.177.70:18822;branch=z9hG4bK-d8754z->a53f3d4a240cb301-1---d8754z-;rport=18822;received=172.20.177.70
>>>>>Contact: <sip:user1 at 172.20.177.70:18822>
>>>>>To: "user1" <sip:user1 at kv-po-ykrapivanb.umc.com.ua>
>>>>>From: "user1" <sip:user1 at kv-po-ykrapivanb.umc.com.ua>;tag=801dfd1e
>>>>
>>>> I've found that if proxy doesn't understand such or similar methods,
>>>> it will forward this request back to sender because of RequestURI.
>>>> Then the sender will send reply (Event Package Not Supported) to
>>>> proxy, and proxy again will forward response to sender.
>>>> So, the sender is appeared to talk itself.
>>>>
>>>> Is this normal operation ?
>>>>
>>>> Thanks.
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>>>
>>
>