[SIPForum-discussion] calculate number of calls
Karthik Ramiya
Karthik_Ramiya at infosys.com
Mon Oct 26 16:29:24 UTC 2009
Hi Chris,
I can see only the layer 2 overhead 6 bytes and the layer 3 overhead which is of 40 bytes that is missing here.
6(Layer2 overhead) + 40(ip_udp_rtp_overhead) + 160(packet or sample size) = 206
206/ 160 * 64000 (g.711) = 82.4 kbps
768 / 82.4 = 9.32 no. of calls.
Hope this helps.
Cheers,
Karthik
________________________________
From: discussion-bounces at sipforum.org [discussion-bounces at sipforum.org] On Behalf Of Chris Anderson [chrisdotanderson at gmail.com]
Sent: Saturday, October 24, 2009 1:40 AM
To: discussion at sipforum.org
Subject: [SIPForum-discussion] calculate number of calls
hello all. i hope this is the right place to post my first question. i'm having a problem calculating the number of calls that can be made at one time. any help would be helpful.
here are the attributes.
codec -g.711
wan bandwidth - 768Kbps
packet header - 6 bytes
payload - 160 bytes
crtp- no.
here is the formula i've been using.
packet header + crtp + payload = x
x / payload * bitrate = y
wan bandwidth / y = # of calls.
or
6 +(no crtp = 0) 0 + 160 = 166
166 / 160 * 64 (g.711) = 66.4
768 / 66.4 = 11.5
# of calls 11.5
i know thats the wrong answer, but i don't know where i'm going wrong.
any help would be great. thanks in advance.
--
Thanks,
Chris Anderson
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